Pipes and Cisterns

Two pipes can fill a tank in $8 \mathrm{h}$ and $12 \mathrm{h}$ respectively whereas an escape pipe can empty it in $6 \mathrm{h}$. If the three pipes are opened at $1$ PM, $2$ PM and $3$ PM respectively, at what time will the tank be filled?

Which of the following statements are necessary to answer the question:

A tank is fitted with two taps A and B. In how much time will the tank be full if both the taps are opened together ?
(i) A is $50$% more efficient than B
(ii) A alone takes $16$ hours to fill the tank
(iii) B alone takes $24$ hours to fill the tank.

A water filling Pipe $P$ is $5 \mathrm{times}$ faster than second Pipe $Q$. If $P$ fills a cistern in $30 \mathrm{minutes}$. How long will it take to fill the tank, when both the pipes are kept in operation simultaneous?

Three taps $A, B$ and $C$ together can fill a tank in $6$ hours. Tap $C$ alone can fill the tank in $12$ hours. To fill the tank, when it is empty, all the three taps are started together. After working $t$ hours, tap $C$ is closed and the tank is filled in $8$ more hours. What is $t$ equal to ?

$2$ pipes $\mathrm{A}$ and $\mathrm{B}$ can fill $66.66\%$ of the tank in $1.6 \mathrm{hours}$ while working together. The tank was initially empty. Pipe $\mathrm{A}$ was kept open for as much time as was required by pipe $\mathrm{B}$ to fill up $33.33\%$ of the tank alone. Then, pipe $\mathrm{B}$ was kept open for half of the required by pipe $\mathrm{A}$ to fill the tank by itself, it was found that the tank was ${\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$6$}\right.}^{\mathrm{th}}$ empty. Find the least time required by any of the pipe to fill the tank fully.

Three taps, A, B and C, can fill a tank in $20$, $30$ and $40$ minutes, respectively. All the taps are opened simultaneously, and after $5$ minutes, tap A is closed and then after another $6$minutes, tap B is closed. At the moment, a leak developed, which can empty the full tank in $60$ minutes. What is the total time required for the tank to get completely full?

A tank can be filled by pipe A in $20$ minutes and pipe B in $30$ minutes. A person left the tank with both pipes open and returned just when the tank should have been full. However, finding that waste pipe C was open, he closed it. In $2.4$ minutes more, the tank will be full. At what time the waste pipe can empty the tank?

Two pipes can separately fill a tank in $16$ hours and $48$ hours, respectively. Both the pipes are opened together to fill the tank, but when the tank is $2/3\mathrm{rd}$ filled, a leakage develops, by which $\frac{1}{2}$ of the water supplied by both pipes leaks out. Find the total time taken to fill the tank

Pipe A takes $2/3$ of the time required by pipe B to fill the tank individually. When an outlet Pipe C is also opened simultaneously with pipe A and pipe B, it takes $75\%$ more time to fill the empty tank than it takes when only pipe A and B are opened together. If it takes $30$ hours to fill when all the three pipes are opened together, then in what time can pipe C empty the full tank operating alone?

Pipe A alone fills the tank in $x$ hours and Pipe B alone fills the tank in $(x – 8)$ hours. If the efficiency of pipe B is double that of pipe A and pipe A fills the tank at $50$ liters per hour, then what is the capacity of the tank?

If $\frac{3}{16}$ of a tank is filled in $15$ minutes, the rest of the tank will be filled in

Taps A and C can fill a tank in $5$ and $20$ hrs respectively. Taps B and D can drain a full tank in $10$and $40$hrs. respectively. If A, B, C and D are opened in a gap of $2$ hrs. in that order the tank gets full in______.

 It takes $6$ hours for one pipe, $X$ to fill $4 \mathrm{ltr}$. How many hours would it take to fill a tank of $12 \mathrm{ltr}$?

Two pipes A and B can fill an empty tank in $10 \mathrm{hours}$ and $16 \mathrm{hours}$, respectively. They are opened alternately for $1 \mathrm{hour}$ each, opening pipe B first. In how many hours, will the empty tank be filled?

It takes $15 minutes$ for pipe $A$ to fill the tank completely and it takes $30 minutes$ for pipe $B$ to fill the tank completely. If both the inlets are opened together, then in $8 minutes$  tank will be filled completely

It takes $10 minutes$ for pipe $A$ to fill the tank completely and it takes $40 minutes$ for pipe $B$ to fill the tank completely. If both the inlets are opened together, then in $8 minutes$  tank will be filled completely

Two pipes fill a tank in $15 minutes$ and $30 minutes$. Then in $10 minutes$ the tank will be filled if both pipes are opened together

Two pipes fill a tank in $20 minutes$ and $60 minutes$. In how much time will the tank be filled if both pipes are opened together

Two pipes $A$ and $B$ can fill a tank separately in $15$ and $30 hrs$ respectively. If both of them are opened together when the tank is initially empty, how much time will it take to completely fill the tank

Two pipes $A$ and $B$ can fill a tank separately in $12$ and $16 hrs$ respectively. If both of them are opened together when the tank is initially empty, then time taken to completely fill the tank is $\frac{48}{7}hrs$